Three rings each of mass m and radius r are so placed that they touch each other. The radius of gyration of the system about the axis as shown in the figure is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Ι = Ι 1 + Ι 2 + Ι 3
Ι 1 = Ι 2 = 
mr 2
Ι 3 = 
∴ Ι = Ι 1 + Ι 2 + Ι 3 = 
mr 2
Moment of inertia = 3mk 2 where k is radius of gyration.
3mk 2 = 
mr 2 ⇒ k = 
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